二叉树的前序,中序,后序遍历
class Solution {
/**
* 前序遍历 中 左 右
*/
public List<Integer> preorderTraversal(TreeNode root) {
List<Integer> result = new ArrayList<Integer>();
preorder(root, result);
return result;
}
public void preorder(TreeNode root, List<Integer> result) {
if (root == null) {
return;
}
result.add(root.val);
preorder(root.left, result);
preorder(root.right, result);
}
/**
* 中序遍历 左 中 右
*
*
*/
public List<Integer> inorderTraversal(TreeNode root) {
List<Integer> q1= new ArrayList<>();
show(root,q1);
return q1;
}
public void show(TreeNode root,List<Integer> list){
if(root == null){
return;
}
show(root.left,list);
list.add(root.val);
show(root.right,list);
}
/**
* 后序遍历 左 右 中
*/
public List<Integer> postorderTraversal(TreeNode root) {
List<Integer> res = new ArrayList<>();
postorder(root, res);
return res;
}
void postorder(TreeNode root, List<Integer> list) {
if (root == null) {
return;
}
postorder(root.left, list);
postorder(root.right, list);
list.add(root.val);
}
}
public class TreeNode {
int val;
TreeNode left;
TreeNode right;
TreeNode() {}
TreeNode(int val) { this.val = val; }
TreeNode(int val, TreeNode left, TreeNode right) {
this.val = val;
this.left = left;
this.right = right;
}
}
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上次更新: 2024/08/09, 16:07:34